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leelee700
Joined: Oct 09, 2006
# Posts: 50
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Posted: 2007-Jun-10 18:31
This is no doubt a very simple thing but can anyone tell the meaning of
!="" in PHP? Basically, understand that != means not equal to but what does it mean to say not equal to 2 quotation marks?
Thanks.
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g1smd
Staff
Joined: Jul 28, 2002
# Posts: 10438
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Posted: 2007-Jun-10 19:02
Not equal to nothing.
So, equal to anything that is something more than nothing, whatever it actually is.
Clear?
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leelee700
Joined: Oct 09, 2006
# Posts: 50
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Posted: 2007-Jun-10 19:08
thanks g1smd but i think im still confused.
can you say what it means in this context:
$Sql = "select * from my_table";
if($searchtext!=""
{
$Sql=$Sql." where " . $searchtext;
}
$Res = mysql_query($Sql);
$Num = mysql_num_rows($Res);
where $searchtext is the text someone has searched for after doing some stuff to it the original input.
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g1smd
Staff
Joined: Jul 28, 2002
# Posts: 10438
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Posted: 2007-Jun-10 19:13
It checks that something, anything, has been typed in.
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leelee700
Joined: Oct 09, 2006
# Posts: 50
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Posted: 2007-Jun-10 19:32
thanks g1smd. now i understand that. what im trying to do is insert an order statement in the $SQL query so that the output is sorted. However, when i do this:
$Sql = "select * from my_table order by $field1 asc";
I get this error:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in....
I've tried inserting the order statement in the the second part also ($Sql=$Sql." where " . $searchtext order by $field1 asc but doesn't work.
Any suggestions on sorting off of that type of query?
Thanks for this help. It's greatly appreciated.
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g1smd
Staff
Joined: Jul 28, 2002
# Posts: 10438
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Posted: 2007-Jun-11 00:08
SQL isn't one of the things I know a lot about.
I would suggest finding a tutorial somewhere, perhaps one with example code, and copying and modifying the few lines that you'll actually need from there.
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Dinkar
Staff
Joined: Aug 12, 2001
# Posts: 4391
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Posted: 2007-Jun-11 01:24
Check your database connection...
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mj1256
Joined: Jun 05, 2006
# Posts: 918
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Posted: 2007-Jun-11 04:13
PHP is case sensitive, make sure you were consistant in your code SQL vs. sql
i've had this error and its usually a case issue
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g1smd
Staff
Joined: Jul 28, 2002
# Posts: 10438
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Posted: 2007-Jun-11 22:28
Good tip!
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